Have 2 identical cars each 1000kg at a speed of 20m/s. The yellow car is stopped by car's brakes in 25m while green car is stopped by concrete barrier in 1.2m. Drivers have same mass(70kg) Driver of yellow car is stopped by seatbelt in 0.150 sec.
Compare impulse they received in stopping. Would that be 70 * (0-20)for yellow car
Green car it would be 70 * (0-20)
How do I calculate average force exerted on each driver?
Is the average force found by F = the mass times the acceleration which is 9.8
Thank you-
I'm so confused I really don't know where or what to try next
Thank you
To calculate the average force exerted on each driver, you can use the formula:
Average force = change in momentum / time
First, let's calculate the change in momentum for the yellow car's driver. The initial momentum of the driver is given by the mass of the driver multiplied by the initial velocity of the car, which is -70 kg * 20 m/s.
The final momentum is zero because the yellow car comes to a stop. So the change in momentum is:
Change in momentum = final momentum - initial momentum = 0 - (-70 kg * 20 m/s)
Change in momentum = 1400 kg·m/s
Next, we need to calculate the time taken for the yellow car's driver to stop. The time given is 0.150 seconds.
Now, let's calculate the average force:
Average force = change in momentum / time = 1400 kg·m/s / 0.150 s
Average force = 9333.33 N
So the average force exerted on the yellow car's driver is approximately 9333.33 Newtons.
Similarly, we can calculate the average force on the green car's driver. The green car's driver also experiences a change in momentum of 1400 kg·m/s and is stopped in a time of 0.150 seconds.
Average force = 1400 kg·m/s / 0.150 s
Average force = 9333.33 N
Therefore, the average force exerted on the green car's driver is also approximately 9333.33 Newtons.