I am not thinking straight anymore and this is due by 9:00pm. My brain feels a little fried at this point. I have been at it all day. Can someone please help me!

(a) An object is placed in front of a convex mirror. Draw a convex mirror (radius of curvature = 15 cm) to scale, and place an object 28 cm in front of it. Make the object height 4 cm. Using a ray diagram, locate the image and measure its height. (Do this diagram on paper. Your instructor may ask you to turn in this work.)
cm (image location, include sign)
cm (image height, include sign)

(b) Now move the object closer to the mirror, so the object distance is 5 cm. Again, locate its image using a ray diagram. .
cm (image location, include sign)
cm (image height, include sign)

(c) As the object moves closer to the mirror, does the magnitude of the image distance become larger or smaller?
larger
smaller
stays the same

(d) As the object moves closer to the mirror, does the magnitude of the image height become larger or smaller?
larger
smaller
stays the same

(e) What is the ratio of the image height when the object distance is 5 cm to that when the object distance is 28 cm? Give your answer to one significant figure.
h5 cm / h28 cm =

The first four are ray diagrams.

http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/refln/u13l4b.html

answer e can be done on the ray diagram also, but there is a formula you can use to check it.

(a) To solve this problem, the first step is to draw a convex mirror to scale, with a radius of curvature of 15 cm. Place the object 28 cm in front of the mirror and make the object height 4 cm. Now, using a ray diagram, we need to locate the image and measure its height. Start by drawing two incident rays from the top and bottom of the object, heading towards the mirror. These rays should be drawn at different angles, one parallel to the principal axis and one heading towards the focal point. To find the image location, extend these rays behind the mirror (dotted lines) and see where they intersect. Measure the distance from the mirror to the image location, including the sign, and label it in cm. Next, draw two reflected rays from the mirror towards the image. These rays should follow the Law of Reflection, which states that the angle of incidence is equal to the angle of reflection. The image height can be measured by drawing a perpendicular line from the top of the object to the principal axis and extending it to the image location. Measure the height of this line, including the sign, and label it in cm. Once you have completed the ray diagram, measure the image location and height, including their respective signs, and write down the values.

(b) Now, for part (b), you need to move the object closer to the mirror so that the object distance is 5 cm. Repeat the process described in part (a) to locate the image using a ray diagram. Draw two incident rays from the top and bottom of the object towards the mirror. Again, extend these rays behind the mirror to find where they intersect. Measure the distance from the mirror to the image location, including the sign, and label it in cm. Also, draw two reflected rays from the mirror towards the image, ensuring they follow the Law of Reflection. Finally, measure the image height by drawing a perpendicular line from the top of the object to the principal axis and extend it to the image location. Measure the height of this line, including the sign, and label it in cm. Write down the values for image location and height.

(c) Part (c) asks whether the magnitude of the image distance becomes larger or smaller as the object moves closer to the mirror. To answer this, compare the values you obtained for the image locations in parts (a) and (b). Specifically, compare the absolute values of the distances, ignoring the signs. If the absolute value of the image distance in part (b) is larger than the absolute value in part (a), the magnitude of the image distance becomes larger. If the absolute value of the image distance in part (b) is smaller than the absolute value in part (a), the magnitude of the image distance becomes smaller. If the absolute values are the same, then the magnitude of the image distance stays the same.

(d) Part (d) asks whether the magnitude of the image height becomes larger or smaller as the object moves closer to the mirror. To answer this, compare the values you obtained for the image heights in parts (a) and (b). Again, compare the absolute values of the heights, ignoring the signs. If the absolute value of the image height in part (b) is larger than the absolute value in part (a), the magnitude of the image height becomes larger. If the absolute value of the image height in part (b) is smaller than the absolute value in part (a), the magnitude of the image height becomes smaller. If the absolute values are the same, then the magnitude of the image height stays the same.

(e) To find the ratio of the image height when the object distance is 5 cm to that when the object distance is 28 cm, divide the absolute value of the image height at 5 cm by the absolute value of the image height at 28 cm. Round your answer to one significant figure and write down the ratio as h5 cm / h28 cm = (value of ratio).

Remember, for accuracy and clarity, it is best to draw the ray diagrams on paper and label all the measurements carefully.