Two cards are drawn without replacement from an ordinary deck of 52 playing cards. What is the probability that both cards are kings if the first card drawn was a king?
I'm thinking its 13/51 but not sure.
See your repost:
http://www.jiskha.com/display.cgi?id=1291733199
the probability of obtaining exactly two 5's in six rolls of a fair die
13/52 * 12/51. W/o replacement means the second king would have l less in both the numerator and denominator so multiply the 2 results.
If you randomly select a card from a well-shuffled standard deck of 52 cards, what is the probability that the card you select is a heart or 10?
To find the probability that both cards are kings, given that the first card drawn was a king, we can follow these steps:
Step 1: Determine the total number of cards remaining in the deck after drawing the first card. Since we start with a standard deck of 52 cards and one king has already been drawn, there are 51 cards left in the deck.
Step 2: Determine the number of remaining kings in the deck. As there are 4 kings in a standard deck, and one king has already been drawn, there are 3 kings remaining in the deck.
Step 3: Calculate the probability of drawing a king as the second card. Since there are 3 kings remaining and 51 cards remaining in the deck, the probability of drawing a king as the second card is 3/51.
Therefore, the probability that both cards are kings, given that the first card drawn was a king, is 3/51, which simplifies to 1/17.
So, your initial intuition was incorrect. The correct probability is 1/17, not 13/51.