Calculate the molarity of an aqueous NaOH soultion if 32.00ml of it is required to titrate. 0.6789 g of oxalic acid to phenolphthalein end point. The balanced chemical equation is
H2C2O4 + 2NaOH-> Na2C2O4 + 2H2O
Calculate the concentration, in molarity, of a solutiion prepared by adding 9 mL of water to 1mL of 0.1 M of HCl
To calculate the molarity (M) of an aqueous NaOH solution, we need to use the formula:
Molarity (M) = (moles of solute) / (liters of solution)
In this case, the solute is NaOH and the solution volume is given as 32.00 mL. However, we need to find the moles of NaOH.
To determine the moles of NaOH, we can use the balanced chemical equation:
H2C2O4 + 2NaOH → Na2C2O4 + 2H2O
From the equation, we can see that the ratio between H2C2O4 and NaOH is 1:2. This means that for every mole of H2C2O4, we need 2 moles of NaOH.
Now, let's calculate the moles of H2C2O4 using the given mass and molar mass.
Step 1: Calculate the moles of H2C2O4
Molar mass of H2C2O4 (oxalic acid) = 2(1.01) + 2(12.01) + 4(16.00) = 90.03 g/mol
Moles of H2C2O4 = (mass of H2C2O4) / (molar mass of H2C2O4)
Moles of H2C2O4 = 0.6789 g / 90.03 g/mol
Moles of H2C2O4 = 0.00754 mol
Since the molar ratio of NaOH to H2C2O4 is 2:1, the moles of NaOH will be twice the amount of H2C2O4.
Step 2: Calculate the moles of NaOH
Moles of NaOH = 2 * (moles of H2C2O4)
Moles of NaOH = 2 * 0.00754 mol
Moles of NaOH = 0.01508 mol
Now, let's convert the volume of the solution to liters.
Step 3: Convert volume to liters
Volume of solution = 32.00 mL = 32.00/1000 L
Volume of solution = 0.032 L
Finally, we can calculate the molarity of the aqueous NaOH solution.
Step 4: Calculate the molarity (M)
Molarity (M) = (moles of NaOH) / (volume of solution)
Molarity (M) = 0.01508 mol / 0.032 L
Molarity (M) = 0.4713 M
Therefore, the molarity of the aqueous NaOH solution is 0.4713 M.