What is the molarity of the resulting solution when 300. mL of a 0.400 M solution is diluted

to 800. mL?

Use proportions:

0.400M * (300/800)
=0.150M

Well, if we're diluting a solution, it's like watering down a drink. So, let's say you have a glass of lemonade that's 0.4 molarity, and you decide to pour in some extra water to make it more, well, refreshing. By adding water, you're diluting the lemonade.

Now, if you initially had 300 mL of 0.4 M solution and you add more water, it means you're increasing the volume, but the amount of solute (lemonade) stays the same. So you end up with a larger glass, but the same amount of sour goodness.

In this case, you're diluting the solution to a total volume of 800 mL. Now, to find the molarity, we need to compare the amount of solute (lemonade again) to the final volume of the solution.

So, we have 300 mL of 0.4 M. But now it's been diluted to 800 mL.

To calculate the new molarity, we can use the formula: initial molarity x initial volume = final molarity x final volume.

Plugging in the values: (0.4 M) x (300 mL) = (final molarity) x (800 mL).

We can rearrange the equation to solve for the final molarity: final molarity = (0.4 M) x (300 mL) / (800 mL).

Doing the math gives us a final molarity of about 0.15 M.

So, we went from a punchy 0.4 M lemonade to a slightly milder 0.15 M lemonade. But hey, it's still deliciously sour!

To find the molarity of the resulting solution when a given solution is diluted, you can use the formula:

M1V1 = M2V2

Where:
M1 = initial molarity of the solution
V1 = initial volume of the solution
M2 = final molarity of the solution (what we want to find)
V2 = final volume of the solution

Given:
M1 = 0.400 M
V1 = 300. mL
V2 = 800. mL

Let's substitute these values into the formula and solve for M2:

M1V1 = M2V2

(0.400 M)(300. mL) = M2(800. mL)

Now, we can solve for M2:

M2 = (0.400 M)(300. mL) / (800. mL)

M2 = 0.150 M

Therefore, the molarity of the resulting solution when 300. mL of a 0.400 M solution is diluted to 800. mL is 0.150 M.

To find the molarity of the resulting solution when a solution is diluted, we can use the formula:

M1V1 = M2V2

Where:
M1 = initial molarity of the solution
V1 = initial volume of the solution
M2 = final molarity of the solution
V2 = final volume of the solution

In this case, the initial molarity (M1) is 0.400 M, the initial volume (V1) is 300. mL, the final volume (V2) is 800. mL, and we want to find the final molarity (M2).

Plugging the values into the formula, we have:

(0.400 M)(300. mL) = M2(800. mL)

Now we can solve for M2:

(0.400 M)(300. mL) / (800. mL) = M2

Calculating this expression, we find:

M2 = 0.150 M

Therefore, the molarity of the resulting solution when 300. mL of a 0.400 M solution is diluted to 800. mL is 0.150 M.