# chemistry

how many grams of Na2CO3 must be dissolved into 155 g of water to create a solution with the molality of 8.20 mol/kg?

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1. MW(Na2CO3)=105.96g/mol

Volume- 155g H20 = 0.155L H20
Concentration- 8.20mol/L

n=CV
n=(8.20mol/L)(0.155L)
n=52.9mol

m=nMW
m=(52.9mol)(105.96g/mol)
m=5605.6g
m=5.61Kg

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posted by Stefan A

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