chemistry

how many grams of Na2CO3 must be dissolved into 155 g of water to create a solution with the molality of 8.20 mol/kg?

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asked by william
  1. MW(Na2CO3)=105.96g/mol

    Volume- 155g H20 = 0.155L H20
    Concentration- 8.20mol/L

    n=CV
    n=(8.20mol/L)(0.155L)
    n=52.9mol

    m=nMW
    m=(52.9mol)(105.96g/mol)
    m=5605.6g
    m=5.61Kg

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    posted by Stefan A

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