Calculate the molarity of a 5.4% sodium hydroxide solution whose density is 1.07 g/mL.
assume 1000 ml
then mass= 1070 g
but 5.4percent,or 1070*.054 is mass of solute.
Molarity= (1070*.054)/molmassNaOH / (1liter)
u r sure. why is mass 1070?
To calculate the molarity of a solution, we need to know the formula weight of the solute (in this case, sodium hydroxide) and the volume of the solution. In this case, we have the percentage concentration and the density of the solution.
1. First, let's determine the mass of sodium hydroxide in the solution. We can do this by using the density and the volume.
Density = mass/volume
Rearranging the equation, we have:
mass = density * volume
Since the density is given as 1.07 g/mL, and we don't have the volume of the solution, we can't determine the exact mass of sodium hydroxide in the solution at this point. We will need more information.
2. To calculate the molarity, we need to know the number of moles of sodium hydroxide. The number of moles can be calculated using the mass of the solute and its formula weight.
Since we don't have the exact mass of sodium hydroxide, we can't calculate the number of moles at this point.
Therefore, without the volume or mass of the solution, we cannot determine the molarity of the 5.4% sodium hydroxide solution.