# algebra 2

27x^3-8=0
(difference of two cubes)

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1. 27x^3-8=0
(3x - 2)(x^2 + 6x + 4) = 0
x = 2/3 or x = ... (2 imaginary roots)

use the quadratic equation formula to find the 2 complex roots.

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posted by Reiny

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