algebra 2

27x^3-8=0
(difference of two cubes)

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asked by Melanie
  1. 27x^3-8=0
    (3x - 2)(x^2 + 6x + 4) = 0
    x = 2/3 or x = ... (2 imaginary roots)

    use the quadratic equation formula to find the 2 complex roots.

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    posted by Reiny

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