An organ pipe is open at one end and has a length of 3 m. What is its fundamental frequency if the speed of sound is 336 m/s?
and it is closed on the other? the pipe is 1/4 wavelength long.
f*4Lengthpipe=336
To find the fundamental frequency of an open organ pipe, we need to use the formula:
f = v / (2L)
where:
f = fundamental frequency (in Hz)
v = speed of sound (in m/s)
L = length of the organ pipe (in m)
Given:
v = 336 m/s
L = 3 m
Plugging the given values into the formula, we have:
f = 336 / (2 * 3)
Now, let's calculate the answer:
f = 168 / 6
f = 28 Hz
Therefore, the fundamental frequency of the open organ pipe is 28 Hz.