If the voltage V, in an electric circuit is held constant,the current,I,is inversely proportional to the resistance,R. If the current is 490 milliamperes when the resistance is 5 ohms,find the current when the resistance is 35 ohms.
I = 490 mA = 0.49A.
V = IR = 0.49 * 5 = 2.45V
I = V / R = 2.45 / 35 = 0.07A = 70 mA.
To solve this problem, we can use the concept of inverse proportionality between the current (I) and the resistance (R). According to the problem, if the voltage (V) is held constant:
I ∝ 1/R
We can write this as an equation:
I = k/R
where k is the constant of proportionality.
To find the value of k, we can use the given information that when the resistance is 5 ohms, the current is 490 milliamperes:
490 = k/5
To find k, we can solve for it:
k = 490 * 5
k = 2450
Now that we know the value of k, we can use it to find the current when the resistance is 35 ohms:
I = 2450/35
I ≈ 70 milliamperes
Therefore, when the resistance is 35 ohms, the current is approximately 70 milliamperes.
To solve this problem, we can use the concept of inverse proportionality between current and resistance.
According to the given information, when the resistance was 5 ohms, the current was 490 milliamperes. Let's call this first set of values I1 and R1:
I1 = 490 milliamperes
R1 = 5 ohms
Now, we need to find the current (let's call it I2) when the resistance is 35 ohms.
Since current is inversely proportional to resistance, we can set up the following proportion:
I1 * R1 = I2 * R2
Substituting the given values:
490 milliamperes * 5 ohms = I2 * 35 ohms
2450 milliamp-ohms = I2 * 35 ohms
To find I2, we can rearrange the equation:
I2 = (2450 milliamp-ohms) / 35 ohms
Now, let's convert milliamperes to amperes by dividing the value by 1000:
I2 = (2450/1000) A / 35 ohms
Simplifying, we have:
I2 = 2.45 A / 35 ohms
I2 ≈ 0.07 A (rounded to two decimal places)
Therefore, when the resistance is 35 ohms, the current will be approximately 0.07 Amperes (or 70 milliamperes).