What are the concentrations of the following solutions:
a) a 200mL aqueous solution containing 4.26g sodium solfate.
b) a 2.00 L aqueous solution containing 107.0g ammonium chloride NH4Cl.
Plz can give me someone the answers for BOTH and the steps how you did it plzzzzzz :)
What concn do you want? There is molarity, molality, mole fraction, percent by mass, percent by volume, percent m/v, normality, and I expect some I've omitted.
To find the concentration of a solution, we use the formula:
Concentration (in g/mL) = Mass of solute (in g) / Volume of solution (in mL)
Let's calculate the concentrations for the given solutions:
a) For a 200 mL aqueous solution containing 4.26 g of sodium sulfate:
- The mass of solute (sodium sulfate) = 4.26 g
- The volume of the solution = 200 mL
Using the formula:
Concentration = 4.26 g / 200 mL = 0.0213 g/mL
Therefore, the concentration of this solution is 0.0213 g/mL.
b) For a 2.00 L aqueous solution containing 107.0 g of ammonium chloride:
- The mass of solute (ammonium chloride) = 107.0 g
- The volume of the solution = 2.00 L (Remember to convert L to mL, since the formula requires mL)
Using the formula:
Concentration = 107.0 g / (2.00 L × 1000 mL/L) = 0.0535 g/mL
Therefore, the concentration of this solution is 0.0535 g/mL.
Now you can use these steps to calculate the concentration of any other solution by following the formula: Concentration = Mass of solute / Volume of solution.