water has a vapor pressure of 23.76 torr at 25C if 1.15 g H2O is enclosed in a 1.0 L container will any liquid be present if so what is the mass of the water?

I would use PV = nRT and solve for n = number of moles H2O in the vapor phase. Compare this with moles H2O in 1.15 g. The difference, if any, will be the moles H2O in liquid form.

To determine whether any liquid will be present in the container, we need to compare the actual vapor pressure of water at 25°C with the vapor pressure of the water vapor present in the container.

The given vapor pressure of water at 25°C is 23.76 torr. However, this is not the vapor pressure of the water vapor in the container, it is the vapor pressure of water at that temperature.

To find the vapor pressure of the water vapor in the container, we can use Raoult's law, which states that the partial pressure of a component in a mixture of non-reacting gases is equal to the vapor pressure of the pure component multiplied by its mole fraction in the mixture.

First, we need to calculate the number of moles of water in the container.

Given:
Mass of water (H2O) = 1.15 g
Molar mass of water (H2O) = 18.02 g/mol

Number of moles of water (H2O) = Mass of water / Molar mass of water
Number of moles of water (H2O) = 1.15 g / 18.02 g/mol

Now, let's calculate the mole fraction of water in the mixture.
We have water only in the container, so the mole fraction of water will be 1.

Next, using Raoult's law, we can calculate the vapor pressure of water vapor in the container.

Partial pressure of water vapor = Vapor pressure of water × Mole fraction of water
Partial pressure of water vapor = 23.76 torr × 1

Comparing the partial pressure of water vapor in the container with the actual vapor pressure of water at 25°C (23.76 torr), we can determine whether any liquid will be present.

If the partial pressure of water vapor in the container is equal to or greater than the actual vapor pressure of water at 25°C, then liquid water will not be present. If it is less than the actual vapor pressure, then liquid water will be present.

So, if the partial pressure of water vapor in the container is 23.76 torr or higher, then there will be no liquid water present. Otherwise, there will be liquid water present.

To find the mass of the water in the container, we need to know if liquid water is present.