# Chemistry

What is the solubility equilibrium for Mn3(PO4)2?

Isn't it this..
Mn3(PO4)2 (s) --> 3Mn^+2 (aq) + 2PO4^-3
(aq)

but i keep getting it wrong. suggestions?

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1. Mn+3(PO4)+2 (s) to be exact**

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2. You wrote the solubility equation correctly (except the arrow, you should have <-->). But I suspect they want the expression to find the solubility constant, which would be

Ks= [Mn++]3[PO32]

where [] means solubility in moles/liter.

https://chemistry.twu.edu/tutorial/KspSum.html

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3. thank you!

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