calc
 👍 0
 👎 0
 👁 332
Respond to this Question
Similar Questions

Trigonometry
Simplify the expression using trig identities: 1. (sin4x  cos4x)/(sin2x cos2x) 2. (sinx(cotx)+cosx)/(2cotx)

trig
sinx = 4/5 and x terminates in Quadrant II Find sin2x and cos2x How to get the answers, which are sin2x = 24/25, cos2x = 7/25?

Trig.......
I need to prove that the following is true. Thanks (2tanx /1tan^x)+(1/2cos^2x1)= (cosx+sinx)/(cosx  sinx) and thanks ........... check your typing. I tried 30ยบ, the two sides are not equal, they differ by 1 oh , thank you Mr

Math
verify the identity (1cosx)/(sinx)+(sinx)/(1cosx)=2cscx Thank you!

Math
(sinx  cosx)(sinx + cosx) = 2sin^2x 1 I need some tips on trigonometric identities. Why shouldn't I just turn (sinx + cosx) into 1 and would it still have the same identity?

Math  Trig  Double Angles
Prove: sin2x / 1  cos2x = cotx My Attempt: LS: = 2sinxcosx /  1  (1  2sin^2x) = 2sinxcosx /  1 + 2sin^2x = cosx / sinx  1 = cosx / sinx  1/1 = cosx / sinx  sinx / sinx  Prove: 2sin(x+y)sin(xy) = cos2y  cos2x My

Trig
Simplify: (cosx + cos2x + cos3x + cos4x + cos5x + cos6x) / (sinx + sin2x + sin3x + sin4x + sin5x + sin6x) into a single Cotangent function. Using the sumtoproducts, I was able to get remove some of the addition in attempts to

PreCalc
Establish the identity. sinx + cosx/sinx  cosx = 1+2sinxcosx/2sin^2x1

Trig
Verify the identity: tanx(cos2x) = sin2x  tanx Left Side = (sinx/cosx)(2cos^2 x 1) =sinx(2cos^2 x  1)/cosx Right Side = 2sinx cosx  sinx/cosx =(2sinxcos^2 x  sinx)/cosx =sinx(2cos^2 x 1)/cosx = L.S. Q.E.D.

Trigonometry
Simplify #1: cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer cscxtanx/sinx+cosx? Simplify #2: sin2x/1+cos2X = ??? I'm stuck on this one. I don't know what I should do.

Maths
Prove that sin2x+cos2x1/sin2x+cos2x+1=tanx

trig
tanx = 5/12 and sinx
You can view more similar questions or ask a new question.