Given the following reaction:
Pd(NO3)2+CaSO4-->PdSO4+Ca(NO3)2
If you started with 225.6ml of 6.32M CaSO4 and the percent yield of this reaction was ol 78.2%, what is the actual yield of grams mod of PdSO4?
Your next to last line doesn't make sense but I assume you want to know how many gram PdSO4 you have at the end of the reaction.
moles CaSO4 = M x L
Using the coefficients in the balanced equation, convert moles CaSO4 to moles PdSO4.
Now convert moles PdSO4 to grams.
g = moles x molar mass. This is the theoretical yield.
Then theoretical yield x 0.782 = g actual yield.
To find the actual yield of PdSO4 in grams, we need to use the given information about the initial volume and concentration of CaSO4 and the percent yield of the reaction.
First, let's convert the initial volume of CaSO4 solution from milliliters to liters:
225.6 ml = 225.6/1000 = 0.2256 L
Next, we can use the formula for molarity (M) to find the number of moles of CaSO4:
moles of CaSO4 = volume (in L) * concentration (M)
moles of CaSO4 = 0.2256 L * 6.32 M
moles of CaSO4 = 1.426112
Now, let's use the balanced equation to determine the molar ratio between CaSO4 and PdSO4:
1 mol CaSO4 : 1 mol PdSO4
Since the ratio is 1:1, the number of moles of PdSO4 formed will also be 1.426112 moles.
Now, we need to calculate the theoretical yield of PdSO4 in grams. The molar mass of PdSO4 is needed for this calculation. The molar mass of PdSO4 can be calculated by adding up the atomic masses of each element:
Molar mass of PdSO4 = (Pd atomic mass) + (S atomic mass) + 4 * (O atomic mass)
Molar mass of PdSO4 = 106.42 + 32.07 + 4 * 16.00
Molar mass of PdSO4 = 239.49 g/mol
Theoretical yield (in grams) = moles of PdSO4 * molar mass of PdSO4
Theoretical yield (in grams) = 1.426112 mol * 239.49 g/mol
Theoretical yield (in grams) = 341.45 g
Since the percent yield is given as 78.2%, we can calculate the actual yield by multiplying the theoretical yield by the percent yield:
Actual yield (in grams) = theoretical yield * percent yield (as a decimal)
Actual yield (in grams) = 341.45 g * 0.782
Actual yield (in grams) = 267.22 g
Therefore, the actual yield of PdSO4 is 267.22 grams.