1.x(x-3)=4 means that x=4 and x-3=4
Is that right?
2.Is the sum of squares prime???
1. no it doesn't
even though by coincidence x = 4 does work, your other solution of x = 7 does not.
What you are assuming to be true only works if the Right Side is equal to zero.
in this case you have to expand it, ..
x^2 - 3x - 4 = 0
(x-4)(x+1) = 0
then x = 4 and x = -1
2. true, because it has no factors other than 1 and itself
.x(x-3)=4 means that x=4 and x-3=4
Is that right?
x^2-3x-4=0
(x-4)(x+1)=0
x1=4 and x2=-1
so if you put x = 4 then x-3 can't be equell to 4
the rule is this: A prime can be written as a sum of
two squares. I hope that helps
1. Let's solve the equation step by step to find the value of x:
Starting with the equation: x(x-3) = 4.
Expand the equation by distributing x: x^2 - 3x = 4.
Rearrange the equation to set it equal to zero: x^2 - 3x - 4 = 0.
We can now factor the quadratic equation: (x-4)(x+1) = 0.
Using the Zero Product Property, we set each factor equal to zero: x-4 = 0 and x+1 = 0.
Solving the first equation, we get x = 4.
Solving the second equation, we get x = -1.
So, the solutions to the equation x(x-3) = 4 are x = 4 and x = -1.
Therefore, x = 4 and x-3 = 4 is not correct.
2. The statement "Is the sum of squares prime???" is not clear. Could you please provide more information or a specific equation to discuss?