physics

A large wooden wheel of radius R and the moment of inertia I is mounted on an axle so as to rotate freely. A bullet of mass m and speed v is shot tangential to the wheel and strike its edge, lodging in the wheel’s rim. If the wheel was originally at rest, what is its rotation rate just after the collision?

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  1. Initial angular momentum about axis =
    Mbullet*Vbullet*R

    This equals the final angular momentum,
    (Iwheel + Mbullet*R^2)*w_final

    w_final = (Mbullet*Vbullet)*R/(Iwheel + Mbullet*R^2)

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