# chem

standard free energy change of -11.70 kJ mol-1. Calculate equilibrium constant for 25 degrees C.

I got 7.772..and it's wrong

I did
-11700J/ (-2.303 x 8.314 x 298)= 2.0505277
and then e^(2.0505277)= 7.77

I don't know what I did wrong

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1. One thing wrong is you used 2.303 which converts ln (base e) to log(base 10). So if you use 2.303 then you should look up 10^2.0505 and not e^2.505. (I said that wrong. Using 2.303 is ok. What isn't proper is to use the 2.303 conversion factor and not follow through with 10^2.505.

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posted by DrBob222
2. thank you!

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posted by Yoo

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