what is the molarity of 275mL of a solution containing 23.83 mg of Mg Cl(2)<small 2

moles = grams/molar mass. Be sure to change mg to grams.

Then M = moles/L of soln.

Oh, I'm glad you asked! Well, to determine the molarity, we need to use the equation Molarity = moles of solute / volume of solution in liters.

First, let's convert the given mass of MgCl₂ (23.83 mg) to moles. The molar mass of MgCl₂ is approximately 95.211 g/mol.

(23.83 mg) / (95.211 g/mol) = 0.25 * 10⁻³ moles of MgCl₂

Next, we need to convert the volume of the solution to liters. Given that you have 275 mL of the solution, we divide by 1000.

(275 mL) / (1000 mL/L) = 0.275 liters

Finally, we substitute the values into the equation:

Molarity = (0.25 * 10⁻³ moles of MgCl₂) / (0.275 liters)

Now, let's calculate the answer. Drumroll, please...

Molarity = 0.9091 mol/L

So, the molarity of the solution is approximately 0.9091 mol/L. Ta-da!

To find the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).

Step 1: Convert the given mass of MgCl2 to moles.
The molar mass of MgCl2 is:
(1 mol of Mg) + (2 mol of Cl) = 24.31 g/mol + 2 * 35.45 g/mol = 95.21 g/mol

To convert mg to g:
23.83 mg * (1 g / 1000 mg) = 0.02383 g

Now, convert grams of MgCl2 to moles:
0.02383 g MgCl2 * (1 mol / 95.21 g) = 0.0002503 mol

Step 2: Convert the volume of the solution to liters.
The given volume is 275 mL.
To convert mL to L:
275 mL * (1 L / 1000 mL) = 0.275 L

Step 3: Calculate the molarity.
Molarity is defined as moles of solute divided by liters of solution:

Molarity (M) = Moles of solute / Volume of solution (in liters)
M = 0.0002503 mol / 0.275 L ≈ 0.000911 M

Therefore, the molarity of the solution is approximately 0.000911 M.

To determine the molarity (M) of a solution, you need to know the number of moles of solute and the volume of the solution in liters.

First, let's calculate the number of moles of MgCl2.

The molar mass of MgCl2 is:
Mg: 24.31 g/mol
Cl: 35.45 g/mol x 2 = 70.90 g/mol

So, the molar mass of MgCl2 is 95.21 g/mol.

To calculate the number of moles, we need to convert the given mass of MgCl2 from milligrams to grams:
23.83 mg = 23.83 g / 1000 = 0.02383 g

Next, we use the formula: Moles = Mass / Molar mass.
Moles of MgCl2 = 0.02383 g / 95.21 g/mol

Now, let's determine the volume in liters.

The given volume is 275 mL. To convert to liters, we divide by 1000:
275 mL = 275 / 1000 = 0.275 L

Finally, we can calculate the molarity (M):

Molarity (M) = Moles / Volume
Molarity (M) = (0.02383 g / 95.21 g/mol) / 0.275 L

Using these values, we can calculate the molarity of the solution by plugging in the values and performing the calculation.

Please note that when performing calculations, it's important to carefully consider units and make sure they are properly converted if needed.