Chem 22

molecular equation, and net ionic equation of
K2SO4 + MgCl2
NiCl2 + NaOH
MgCl2 + NaOH
K2SO4 + NaOH
Ba(OH)2 + NiCl2
Ba(OH)2 + MgCl2
Ba(OH)2 + K2SO4
Ba(OH)2 + NaOH
Na2CrO4 + Sr(NO3)2
Na2CrO4 + Al2(SO4)3
K2CrO4 + Sr(NO3)2
K2CrO4 + Al2(SO4)3
AgNO3 + BaCl2
AgNO3 + Na2CrO4
AgNO3 + Al2(SO4)3
AgNO3 + K2CrO4

Thank you! I really Appreciate it!

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  1. I will show you how to do one and then you can have a go at the others. First decide if the mixture will give you a reaction, a precipitate. If there is no reaction there is neither a molecular equation or a net ionic equation.

    Start with the molecular formula

    Na2CrO4(aq) + Sr(NO3)2(aq) -> NaNO3(aq) + SrCrO4(s)

    balance the equation

    Na2CrO4(aq) + Sr(NO3)2(aq) -> 2NaNO3(aq) + SrCrO4(s)

    write in all the ions

    2Na+(aq) + CrO4^2-(aq) + Sr^2(aq)+2NO3-(aq)->
    2Na2+(aq)+ 2NO3-(aq) + SrCrO4(s)

    now you delete ions that appear on each side, so you end up with

    CrO4^2-(aq) + Sr^2(aq)->
    SrCrO4(s)

    which is the net ionic equation.

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    posted by Dr Russ
  2. Mgcl+k2SO4

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    posted by Robiya

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