is Br2(L)+Cl2(g)--->BrCl(g) a balanced equation?
No, but
Br2+Cl2---> 2BrCl
is balanced
Br2+Cl2<-->2BCl
yes
No two anions may be put together in an ionic compound. Cl and Br are both negatively charged. You could put BACl2 for example.
To determine if the equation Br2(L) + Cl2(g) ---> BrCl(g) is balanced, we need to check if the number of atoms of each element is the same on both sides of the equation.
Let's break it down step-by-step:
1. Count the number of Br (bromine) atoms:
There are 2 Br atoms on the left side (Br2) and 1 Br atom on the right side (BrCl).
2. Count the number of Cl (chlorine) atoms:
There are 2 Cl atoms on the left side (Cl2) and 1 Cl atom on the right side (BrCl).
Since the number of atoms of each element are not equal on both sides, the equation is not balanced.
To balance it, we need to adjust the coefficients (the numbers in front of the compounds or elements) to ensure the same number of each element on both sides of the equation.
Let's balance it together:
Br2(L) + Cl2(g) ---> 2BrCl(g)
By adding the coefficient 2 in front of BrCl, we now have 2 bromine atoms and 2 chlorine atoms on both sides of the equation.
Therefore, the balanced equation is:
Br2(L) + Cl2(g) ---> 2BrCl(g)