A 0.70 kg ball is moving horizontally with a speed of 8.8 m/s when it strikes a vertical wall. The ball rebounds with a speed of 3.7 m/s. What is the magnitude of the change in linear momentum of the ball?
-I am not sure how to honestly to figure this one out.
final momentum - initial momentum
m(Vf)-m(-Vi)= (notice the negative sign in the second velocityk, it is going opposite to final velocity.
To find the magnitude of the change in linear momentum of the ball, you need to use the formula:
Change in linear momentum (Δp) = Final linear momentum (p_f) - Initial linear momentum (p_i)
Linear momentum, also known as momentum, is defined as the product of an object's mass and its velocity.
In this case, the initial linear momentum (p_i) of the ball can be calculated as:
p_i = mass (m) × initial velocity (v_i)
Given:
Mass (m) = 0.70 kg
Initial velocity (v_i) = 8.8 m/s
So, p_i = 0.70 kg × 8.8 m/s
Now, let's calculate the final linear momentum (p_f) of the ball:
p_f = mass (m) × final velocity (v_f)
Given:
Mass (m) = 0.70 kg
Final velocity (v_f) = 3.7 m/s
So, p_f = 0.70 kg × 3.7 m/s
Finally, you can calculate the magnitude of the change in linear momentum (Δp) by subtracting the initial linear momentum (p_i) from the final linear momentum (p_f):
Δp = p_f - p_i
Now, you can substitute the calculated values into the equation and solve for Δp.