Can you please help me with the following problem?

Two charges separated by one meter exert 1-N forces on each other. If the charges are pushed to 1/4 meter separation, the force on each charge will be?

The inverse law applies. What is the reciprocal of 1/4 squared? As charges get closer, the force increases dramatically?

Would it be 16 N?

Yes.

What is the pressure

What is the solution?

Sure! To solve this problem, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for the force (F) between two charges (q1 and q2) is given by:

F = k * |q1 * q2| / d^2

where k is the electrostatic constant and d is the distance between the charges.

Given that the force between the charges is 1 N when they are 1 meter apart, we can write the equation:

1 N = k * |q1 * q2| / (1 m)^2

To find the force when the charges are pushed to 1/4 meter separation, we need to calculate the new force using the new distance (d').

Let's substitute the values into the equation:

1 N = k * |q1 * q2| / (1/4 m)^2

Simplifying this equation, we can rearrange it to solve for the new force (F'):

F' = (1 N) * (1/16) = 1/16 N

Therefore, when the charges are pushed to 1/4 meter separation, the force on each charge will be 1/16 N.