Find the area of each figure with the given dimensions
Trapeziod: b1 = 6,b2=10, h=5
Trapeziod: b1= 4.5, b2= 8, h=6.7
I wasn't in school the day we studied this, and i am only in 7th grade!
the formula for area of a trapezoid is A = h (b1 + b2) all over 2. So, for the first trapezoid, you would have:
5 (6 + 10) / 2 = 40. For the second trapezoid, you would have:
6.7 (4.5 + 8)/ 2 = 94.6375
5-2
Why is a parallelagram never a trapezoid
No worries! I'll explain how to find the area of a trapezoid and then help you solve the two problems.
To find the area of a trapezoid, you can use the formula:
Area = (1/2) × (b1 + b2) × h
where b1 and b2 are the lengths of the parallel bases, and h is the height or perpendicular distance between the bases.
Now let's solve the problems!
1. Trapezoid: b1 = 6, b2 = 10, h = 5
Using the formula, plug in the values:
Area = (1/2) × (6 + 10) × 5
= (1/2) × 16 × 5
= 8 × 5
= 40
So, the area of the trapezoid is 40.
2. Trapezoid: b1 = 4.5, b2 = 8, h = 6.7
Using the formula, substitute the given values:
Area = (1/2) × (4.5 + 8) × 6.7
= (1/2) × 12.5 × 6.7
= 6.25 × 6.7
= 41.875
Therefore, the area of the trapezoid is approximately 41.875.
Remember, the area is always measured in square units (e.g., square centimeters, square inches). Make sure to include the appropriate units in your answer.
Hope this helps, and if you have any more questions, feel free to ask!