Consider a level flight turn of a propeller-driven airplane in which the airplane makes a complete circular turn in 1.6 min. If the plane's speed is 200 m/s, what is the radius of the circle?
(2*pi*R)/96 s = 200 m/s
Solve for R in meters
R = 200*96/(2*pi) = ____ m
Change the answer to km if you wish.
I get about 3 km
To find the radius of the circle, we can use the formula for centripetal acceleration:
a = (v^2) / r
Where:
a = centripetal acceleration
v = velocity of the airplane
r = radius of the circle
In a level flight turn, the weight of the airplane acts as the centripetal force:
F = m * g = m * a
Where:
F = centripetal force
m = mass of the airplane
g = acceleration due to gravity (approximately 9.8 m/s^2)
Since the weight of the airplane is equal to the centripetal force, we can set the equations equal to each other:
m * g = (v^2) / r
Solving for r, the radius of the circle:
r = (v^2) / (m * g)
Now we can substitute the given values:
v = 200 m/s
m = unknown
g = 9.8 m/s^2
To find the unknown mass, we need more information. Please provide the mass of the airplane.