what is the molarity of an unknown HCI concentration if it requires 75ml of a 0.2 M NaOH solution?
mL x M = mL x M
To determine the molarity of the unknown HCI concentration, we can use the concept of stoichiometry and the balanced chemical equation. Here's how to approach it:
Step 1: Write the balanced chemical equation for the reaction between HCl and NaOH:
HCl + NaOH -> NaCl + H2O
Step 2: Determine the stoichiometric ratio between HCl and NaOH from the balanced equation. In this case, the stoichiometric ratio is 1:1, meaning one mole of HCl reacts with one mole of NaOH.
Step 3: Use the given information and the stoichiometric ratio as a conversion factor to find the moles of HCl. Given that 75 mL of a 0.2 M NaOH solution is used, we can use the following calculation:
Moles of NaOH = Volume (L) × Concentration (M)
Moles of NaOH = 0.075 L × 0.2 M = 0.015 mol
Since the stoichiometric ratio is 1:1, the moles of HCl in the reaction are also 0.015 mol.
Step 4: Determine the molarity of the HCl solution using the volume of the solution. Let's assume the volume of the HCl solution is V (in liters) and its molarity is M (in moles per liter or M).
Moles of HCl = Volume (L) × Concentration (M)
0.015 mol = V × M
Since we don't have the specific volume of the HCl solution, we cannot directly calculate the molarity. However, we can determine the relationship between the volume and the concentration.
Step 5: Use the equation Moles of HCl = Volume (L) × Concentration (M) to solve for M (molarity):
M = Moles of HCl / Volume (L)
Therefore, the molarity of the unknown HCl concentration depends on the volume of the HCl solution used. Without the specific volume, we cannot calculate the molarity accurately.