Write an equation of the line that passes through the point ( 8,3) and has the slope of 1/4
So, I think you would write it as Y=1/4x+B
and, you'd plug in 8 for the x, and 1 for the y.
So you'd get 1=1/4(4) + B
And you'd get.. 1=1+B
So, subtract one from each side
0=b
y=1/4x+B
Is my answer correct?
Thanks
where does the 8 come into the problem at?
you would plug x=8 and y=3 into your y=1/4x+b formula..you eventually get the answer to be 1
yes y = (1/4) x + b
but
3 = (1/4)(8) + b
3 = 2 + b
b = 1
y = x/4 + 1
check
if x = 8
y = 8/4+ 1
y = 2 + 1
y = 3
yes (8,3)
Thank you all.
Yes, you are on the right track! Let's go through the steps more explicitly to confirm your answer:
To find the equation of a line, we can use the slope-intercept form: y = mx + b, where m represents the slope and b represents the y-intercept.
Given that the line passes through the point (8, 3) and has a slope of 1/4, we can substitute these values into the equation.
1. Start with the slope-intercept form: y = mx + b
2. Substitute the given slope, m = 1/4: y = (1/4)x + b
3. Now, substitute the coordinates of the point (8, 3) into the equation:
y = (1/4)(8) + b
Simplify the right side: y = 2 + b
4. We know that the point (8, 3) lies on the line, so we can substitute the coordinates into the equation to solve for b:
3 = 2 + b
5. Solve for b:
Subtract 2 from both sides: 3 - 2 = b
b = 1
6. Plug the value of b into the equation:
y = (1/4)x + 1
So, your final answer is y = (1/4)x + 1. Great job!