A balloon at contains 0.5 L of gas at a constant pressure of 1.0 atm. If the pressure is increased to 3.0 atm, what will be the volume of the gas?

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law formula is expressed as:
P1 * V1 = P2 * V2

Where:
P1 is the initial pressure (1.0 atm)
V1 is the initial volume (0.5 L)
P2 is the final pressure (3.0 atm)
V2 is the final volume (unknown)

Rearranging the formula to isolate V2, we get:
V2 = (P1 * V1) / P2

Now we can substitute the known values into the equation:
V2 = (1.0 atm * 0.5 L) / 3.0 atm

Simplifying, we have:
V2 = 0.5 L / 3.0

V2 equals approximately 0.167 L.

Therefore, when the pressure is increased from 1.0 atm to 3.0 atm, the volume of the gas will decrease to 0.167 L.