The mass of a golf ball is 45.9g. If it leaves the tee with a speed of 72.0 m/s, what is its corresponding wavelength?
Express your answer numerically in meters.
Would the correct answer be:
lambda=h/mv
lambda=6.626*10^-34/(45.9g)(72.0m/s)
lambda=2.00*10^-37 ???
Is the question this easy or is there some conversion that I am missing??
2.0*10^-34 was correct.
2.0*10^-34 was correct. Thank you.
You are talking about the DeBroglie wavelength, a concept from quantum mechanics. It is equal to Planck's constant, h = 6.62*10^-34 J, divided by the momentum M v of the golf ball. You will find it to be very short compared to the size of the golf ball.
You have the right formula but you must express the mass in kg, not grams, since you are using SI units for h.
so...would I find the answer to be:
lambda=6.626*10^-34 J s/(0.0459kg)(72.0m/s)
answer= 2.00*10^-34
or should I have squared the 72.0m/s velocity?
1.85×10−34m NOT 1.95×10−34m
To find the corresponding wavelength of a golf ball leaving the tee with a given mass and speed, you need to apply the de Broglie wavelength equation. The equation is:
λ = h / (mv)
Where:
λ is the wavelength
h is the Planck's constant (6.626 x 10^-34 J*s)
m is the mass of the golf ball (convert it to kilograms: 45.9 g = 0.0459 kg)
v is the speed of the golf ball (72.0 m/s)
Now, let's plug in the values and solve for λ:
λ = (6.626 x 10^-34 J*s) / (0.0459 kg * 72.0 m/s)
Calculating this equation gives us:
λ = 1.767 × 10^-34 m
So, the corresponding wavelength of the golf ball leaving the tee is approximately 1.767 × 10^-34 meters.