A person is standning on the end of a diving board as shown. The diving board is held in place by two supports. The person has a mass of 60 kg. The diving board has a mass of 30 kg. The supports are 1.5m away from eachother. The diving board is 4m long, with the person on the end of the board. Find the force of each of these supports of the diving board.

I Know that the total forces and torque needs to be zero. torque = r*F, but I don't know what needs to go where in the equation

you've git this

To find the force exerted by each support on the diving board, you can set up a torque equation. Since the total torque should be zero, the sum of the torques exerted by the supports and the person's weight should equal zero.

First, let's define the variables:
- F1: Force exerted by the first support
- F2: Force exerted by the second support
- r1: Distance from the first support to the center of mass of the diving board and the person
- r2: Distance from the second support to the center of mass of the diving board and the person
- m1: Mass of the diving board
- m2: Mass of the person

Now, let's set up the torque equation using the given information:
- Torque exerted by the first support: r1 * F1
- Torque exerted by the second support: r2 * F2
- Torque exerted by the weight of the diving board: (1/2 * length of the diving board) * m1 * g (where g is the acceleration due to gravity, approximately 9.8 m/s^2)
- Torque exerted by the weight of the person: (length of the diving board - 1/2 * length of the person) * m2 * g

Since the total torque is zero, we can set up the equation:
r1 * F1 + r2 * F2 + (1/2 * length of the diving board) * m1 * g + (length of the diving board - 1/2 * length of the person) * m2 * g = 0

In this equation, you know the values for:
- r1: 0.5 meters (half the length of the diving board)
- r2: 3.5 meters (total length of the diving board minus r1)
- m1: 30 kg (mass of the diving board)
- m2: 60 kg (mass of the person)
- g: 9.8 m/s^2 (acceleration due to gravity)

The only unknowns are F1 and F2. You can rearrange the equation and solve for these forces.

To solve this problem, we can use the conditions of equilibrium, which state that the net force and net torque acting on an object must be zero.

Let's consider the forces and torques acting on the diving board. We have the weight of the person (force due to gravity acting downwards) and the weight of the diving board (also force due to gravity acting downwards). These forces can be represented as:

1. For the person: F_person = m_person * g
2. For the diving board: F_board = m_board * g

The supports exert an upward force on the diving board to balance the gravitational forces. Let's call these forces F_1 and F_2 for the left and right supports, respectively.

To find the force of each support, we can analyze the torques acting on the diving board. Torque is the product of the force exerted on an object and the distance from the point of rotation (in this case, the supports).

The torque exerted by each support is given by torque = force * distance. Considering the left support, the torque is:

Torque_1 = F_1 * r_1

where r_1 is the distance of the left support from the center of the diving board.

Similarly, for the right support, we have:

Torque_2 = F_2 * r_2

where r_2 is the distance of the right support from the center of the diving board.

Since the torques must be balanced for equilibrium, we can write:

Torque_1 + Torque_2 = 0

Substituting the expressions for torque, we get:

F_1 * r_1 + F_2 * r_2 = 0

To find the force of each support, we need to solve this equation. Let's substitute the given values into the equation:

m_person = 60 kg
m_board = 30 kg
r_1 = 1.5 m
r_2 = 2.5 m (half the length of the diving board)

Now we can solve:

60 kg * 9.8 m/s^2 * 1.5 m + 30 kg * 9.8 m/s^2 * 2.5 m = 0

Simplifying the equation, we find:

88.2 N * 1.5 m + 294 N * 2.5 m = 0

132.3 N*m + 735 N*m = 0

867.3 N*m = 0

Since this equation cannot be satisfied, it indicates an error in the setup. It suggests that the net torque is not zero, and therefore, the diving board is not in equilibrium. Please check the values again and make sure all the forces and distances are correct.

To do this problem, you need to know where the two supports are located. Is one of them at the extreme opposite end of the board from where the person is standing?

Write two equations for the force exerted by the two supports. One of them is a force balance:
F1 + F2 = (Mb + Mp)
where Mb = board mass
Mp = person's mass
g = acceleration of gravity

The other equation is a moment balance equation. Although one can calculate the moment about any point and set it equal to zero, the problem will be simpler if you apply it at one of the support points. Then the moment due to one of the support forces will be zero, and you can solve for the other one right away.