The net ionic equations for the following

1. Dissolution of silver oxalate with nitric acid
2. Complexation of the iron(III) by the thiocyanate ion
3. Precipitation of the carbonate ion with barium ion
4. precipitation of the oxalate ion with barium ion
5. precipitation of the phosphate ion with barium ion
6. precipitation of the sulfate ion with barium ion
7. dissolution of barium phosphate with hydrochloric acid.

Drbob222 just give him the answers please i need them too

1. Dissolution of silver oxalate with nitric acid:

Ag2C2O4(s) + 2 H+(aq) → 2 Ag+(aq) + C2O4^2-(aq) + H2O(l)

2. Complexation of iron(III) by the thiocyanate ion:
Fe^3+(aq) + 3 SCN^-(aq) → Fe(SCN)3(s)

3. Precipitation of the carbonate ion with barium ion:
Ba^2+(aq) + CO3^2-(aq) → BaCO3(s)

4. Precipitation of the oxalate ion with barium ion:
Ba^2+(aq) + C2O4^2-(aq) → BaC2O4(s)

5. Precipitation of the phosphate ion with barium ion:
Ba^2+(aq) + PO4^3-(aq) → BaPO4(s)

6. Precipitation of the sulfate ion with barium ion:
Ba^2+(aq) + SO4^2-(aq) → BaSO4(s)

7. Dissolution of barium phosphate with hydrochloric acid:
Ba3(PO4)2(s) + 6 HCl(aq) → 3 Ba^2+(aq) + 2 PO4^3-(aq) + 6 Cl^-(aq)

To determine the net ionic equations for the given reactions, we need to balance the chemical equations and identify the ions that are involved in forming the products.

1. Dissolution of silver oxalate with nitric acid:
First, let's write the balanced chemical equation:
Ag2C2O4(s) + 2HNO3(aq) -> 2AgNO3(aq) + H2C2O4(aq)

Next, we can write the net ionic equation by separating the soluble ionic compounds into their respective ions:
Ag2C2O4(s) + 2H+(aq) -> 2Ag+(aq) + C2O4^2-(aq)

2. Complexation of iron(III) by the thiocyanate ion:
The balanced chemical equation is:
Fe^3+(aq) + 3SCN^-(aq) -> Fe(SCN)3(s)

The net ionic equation can be written as:
Fe^3+(aq) + 3SCN^-(aq) -> Fe(SCN)3(s)

3. Precipitation of the carbonate ion with barium ion:
The balanced chemical equation is:
Ba^2+(aq) + CO3^2-(aq) -> BaCO3(s)

The net ionic equation can be written as:
Ba^2+(aq) + CO3^2-(aq) -> BaCO3(s)

4. Precipitation of the oxalate ion with barium ion:
The balanced chemical equation is:
Ba^2+(aq) + C2O4^2-(aq) -> BaC2O4(s)

The net ionic equation can be written as:
Ba^2+(aq) + C2O4^2-(aq) -> BaC2O4(s)

5. Precipitation of the phosphate ion with barium ion:
The balanced chemical equation is:
3Ba^2+(aq) + 2PO4^3-(aq) -> Ba3(PO4)2(s)

The net ionic equation can be written as:
3Ba^2+(aq) + 2PO4^3-(aq) -> Ba3(PO4)2(s)

6. Precipitation of the sulfate ion with barium ion:
The balanced chemical equation is:
Ba^2+(aq) + SO4^2-(aq) -> BaSO4(s)

The net ionic equation can be written as:
Ba^2+(aq) + SO4^2-(aq) -> BaSO4(s)

7. Dissolution of barium phosphate with hydrochloric acid:
The balanced chemical equation is:
Ba3(PO4)2(s) + 6HCl(aq) -> 2H3PO4(aq) + 3BaCl2(aq)

The net ionic equation can be written as:
2PO4^3-(aq) + 6H+(aq) -> 2H3PO4(aq)

You can't do ANY of these? I see a systemic problem rather than a every now and then problem. What's the problem? Perhaps I can help you through it.