How many games are played in a women's soccer conference if there are eight teams and all teams play each other twice?
I figured 8x7x2=112 since this is 8 teams and 7 opponents per team and playing twice am i right?
lets try it manually with four teams, ABCS
AB
AD
AC
BD
BC
CD
So your method doesnt work for four teams.
NOW consider if it were 4*3/2=6 That works. So is the answer now 8*7/2
Hint: one divides by two because AB is the same as BA.
No, your calculation is not correct. Since there are eight teams in the conference, each team will play against seven other teams (excluding themselves). However, since each team plays every other team twice, we need to double the number of games for each matchup.
To calculate the total number of games, you can use the formula:
Total number of games = (Number of teams) x (Number of opponents per team) x 2
In this case, there are eight teams, and each team will play against seven opponents. Therefore, the correct calculation would be:
Total number of games = 8 x 7 x 2 = 112
So, you were right after all! There will be a total of 112 games played in a women's soccer conference with eight teams if each team plays each other twice.