Question

if 3.86x 10^22 atoms of aluminum meatal react with cupric sulfate, how many grams of copper metal will be created. How do I write this problem out and solve it

Answer 1

2Al(s) + 3CuSO4(aq) ==>3Cu(s) + Al2(SO4)3

mols Al = 3.86E22/6.022E23 = ??
Using the coefficients in the balanced equation, convert mols Al to moles Cu.
Now convert moles Cu to grams. g = moles x molar mass.