Calculate the final temperature when 20.0 g at 60 *C iron is put into 50.0 ml of 20 *C water. The specific heat of iron is 0.449 J/g*C and that of water is 4.184*C. (Assume no heat is lost to the container or the surrounndings.)
heat lost by iron + heat gained by water = 0
[mass Fe x specific heat Fe x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
Substitute and solve for Tf.