Find the force on a proton, with kinetic energy 10keV, that is moving perpendicular to a magnetic field of magnitude 2.0kG.

I know I need to find the velocity, and then use F=qvBsinTHETA, but I'm so bad at equating different parts of formulas. Can anyone tell me what to do first?
Thanks

Sure! To find the force on a proton moving perpendicular to a magnetic field, you can follow these steps:

Step 1: Find the velocity of the proton.
You can use the kinetic energy (KE) provided in the question to find the velocity. The kinetic energy is given as 10 keV (kilo-electron volts), which can be converted into joules (J).

1 keV = 1.6 x 10^−16 J

So, 10 keV = 10 × (1.6 x 10^−16 J)

Calculate the value to find the kinetic energy in joules.

Step 2: Calculate the velocity of the proton.
The kinetic energy of a moving object can be expressed using the equation KE = (1/2)mv^2, where m is the mass of the object and v is its velocity.

Rearrange the equation to solve for velocity:

v = √ (2KE / m)

The mass of a proton is approximately 1.67 x 10^-27 kg. Substitute this value and the calculated kinetic energy into the equation to find the velocity.

Step 3: Calculate the force on the proton.
Now that you have the velocity of the proton, you can find the force acting on it using the equation:

F = qvB sinθ

In this equation:
- F represents the force on the proton.
- q is the charge of the proton (constant value of 1.6 x 10^-19 C).
- v is the velocity of the proton (calculated in step 2).
- B is the magnitude of the magnetic field (given as 2.0 kG).
- θ is the angle between the velocity vector and the magnetic field vector, in this case, 90 degrees.

Substitute the values into the equation and calculate the force.

That's it! Follow these steps to find the force on the proton with the given conditions.