Julianne plans to take advantage of the after Thanksgiving sale to purchase the portable DVD player she wants. She finds it on sale at two different stores at the local mall. J-Mart advertises the DVD player for $48.00, while Better Buy has the same model on sale for 20% off the original price, plus their ad includes a $5 off coupon. If the original price for the portable DVD player at each store is $69.99, at which store will Julianne pay the least amount of money to purchase it during the after Thanksgiving sale?
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At J-Mart a portable DVD player carrying case and set of headphones regularly sell for $34.99 and $29.99, respectively. Julianne notices that the carrying case has been drastically reduced. It is on sale for 70% off, and the price of the headphones has been reduced to $18.99 during the after Thanksgiving sale. Based on this information and the previous problem, what is the total combined percent of savings for all three items, if Julianne decides to purchase the portable DVD player, headphones and carrying case from J-Mart during the after Thanksgiving sale? Express your answer to the nearest whole percent.
69.99 - .2(69.99) - 5 = ? Is that more or less than $49?
Insufficient data. You give no indication of the price of the DVD player itself.
To find out where Julianne will pay the least amount of money to purchase the portable DVD player during the sale, we need to compare the prices at both stores.
At J-Mart, the DVD player is advertised for $48.00.
At Better Buy, the original price of the DVD player is $69.99. It is on sale for 20% off, so the sale price is 80% of the original price.
Sale price = 80% of $69.99 = $55.99.
Better Buy also has a $5 off coupon, so the final price at Better Buy is $55.99 - $5 = $50.99.
Comparing the prices, we can see that Julianne will pay the least amount at Better Buy, where the DVD player costs $50.99.
Now let's move on to the second part of the question.
At J-Mart, the carrying case is on sale for 70% off the regular price of $34.99.
Sale price of carrying case = 30% of $34.99 = $10.50.
The headphones are on sale for $18.99.
To find the total combined percent of savings for all three items, we need to calculate the total regular price and the total sale price.
Total regular price = $69.99 (DVD player) + $34.99 (carrying case) + $29.99 (headphones) = $134.97.
Total sale price = $50.99 (DVD player at Better Buy) + $10.50 (carrying case at J-Mart) + $18.99 (headphones at J-Mart) = $80.48.
To find the percent of savings, we can use the formula:
Percent of savings = (Total regular price - Total sale price) / Total regular price * 100.
Percent of savings = ($134.97 - $80.48) / $134.97 * 100 ≈ 40.3.
Therefore, the total combined percent of savings for all three items if Julianne decides to purchase them from J-Mart during the after Thanksgiving sale is approximately 40%.