In an isosceles trapezoid, the longest base is 11", a leg is 5", and the height is 4".
Find the length of the shorter base of the trapezoid.
To find the length of the shorter base of the trapezoid, we can use the formula for the area of a trapezoid, which is given by:
Area = (1/2) * (sum of the bases) * height
Since the trapezoid is isosceles, we can assume the shorter base to be 'x'. Therefore, the sum of the bases would be 'x + 11'.
Given that the height is 4 inches, we can write the equation for the area as:
A = (1/2) * (x + 11) * 4
Now, let's substitute the known values into the equation and solve for 'x'.
A = (1/2) * (x + 11) * 4
Given that the area is not provided in the question, we cannot directly find the value of 'x'. If you provide the area of the trapezoid, I can help you further.
To find the length of the shorter base of the trapezoid, we can use the formula for the area of a trapezoid:
Area = (1/2) * (sum of the bases) * height
In this case, we know the longer base (11"), the height (4"), and we need to find the shorter base. Let's call the length of the shorter base "x".
The area of the trapezoid is also equal to the product of the height and the average of the bases:
Area = (1/2) * (sum of the bases) * height
Area = (1/2) * (11" + x) * 4"
Since we know the area of the trapezoid, we can set up an equation:
Area = (1/2) * (11" + x) * 4" = (1/2) * 11" * 4"
(11" + x) * 4" = 11" * 4"
11" + x = 11"
x = 11" - 11"
x = 0"
Therefore, the length of the shorter base of the isosceles trapezoid is 0".
The non-parallel sides of an isosceles
trapezoid are equal and form congruent rt triangles when the altitude is drawn. The base of the rt tiangles can be calculated:
X^2 + Y^2 = Z^2,
X^2 + 4^2 = 5^2,
X^2 + 16 = 25,
X^2 = 25 - 16,
X^2 = 9,
X = 3.
2X + B2 = B1,
2*3 + B2 = 11,
6 + B2 = 11,
B2 = 11 - 6,
B2 = 5.