Thanks you alot for correction. A car is travelling with a 5m/s in 25 minutes at a distance of 30 cm calculate initial velocity and decelaration of the car.
To solve this problem, we need to convert the given information into consistent units. The car's initial velocity is already given as 5 m/s, which is the standard unit for velocity. However, the time and distance provided are not in consistent units.
First, let's convert the given time of 25 minutes to seconds. Since 1 minute is equal to 60 seconds, we can multiply the given time by 60:
25 minutes * 60 seconds/minute = 1500 seconds
Now, we have the time in seconds.
Next, let's convert the given distance of 30 cm to meters. Since 1 meter is equal to 100 centimeters, we can divide the given distance by 100:
30 cm / 100 cm/m = 0.3 meters
Now, we have the distance in meters.
Using the equations of motion, we can calculate the deceleration of the car. The equation we can use is:
v^2 = u^2 + 2as
where
v = final velocity
u = initial velocity
a = acceleration
s = distance
In this case, the final velocity (v) is 0 m/s because the car comes to a stop.
Rearranging the equation, we have:
u^2 = -2as
Substituting the known values:
(5 m/s)^2 = -2 * a * 0.3 m
25 m^2/s^2 = -0.6 a
To find the deceleration (a), we can rearrange the equation again:
a = -(25 m^2/s^2) / 0.6 m
Simplifying this expression gives us:
a ≈ -41.7 m/s^2
The approximate value of the deceleration is -41.7 m/s^2.
Therefore, the initial velocity is 5 m/s and the deceleration of the car is approximately -41.7 m/s^2.