a hydrated salt is a solid that includes water molecules within its crystal structure. a student heated a 9.10-gram sample of a hydrated salt to a constant mass of 5.41 grams. what percent by mass of water did the salt contain?
It's 40.5%
mass water = 9.10-5.41 = ??
%H2O = (mass H2O/mass sample)*100 = ?
is the answer 40.5% or 59.5% ?
Frankly, I don't think you can get that, either, at least not legally.
mass water = 9.10-5.41 = 3.69 g H2O. I don't know how you converted that into percent; however, take the 3.69 g, substitute into the percent formula I gave you and solve for % H2O.
Post your work if you get stuck.
9.10-5.41=3.69
18.0152/3.69=??
To determine the percentage by mass of water in the hydrated salt, we need to compare the mass of water to the total mass of the sample.
The initial mass of the hydrated salt is 9.10 grams, while the mass after heating it to a constant mass is 5.41 grams. The difference in mass between these two measurements represents the mass of water that was lost during the heating process.
Mass of water lost = Initial mass - Final mass
= 9.10 g - 5.41 g
= 3.69 g
Now, we can calculate the percentage by mass of water in the hydrated salt using the following formula:
Percentage by mass of water = (Mass of water lost / Initial mass) * 100%
Substituting the values:
Percentage by mass of water = (3.69 g / 9.10 g) * 100%
Calculating the result:
Percentage by mass of water = 40.54%
Therefore, the hydrated salt originally contained approximately 40.54% water by mass.
well i got 3.69% but that doesnt look right
Look. Just follow the instructions. You posted a question, I gave you the answer, now you're making up your own answer. I have copied my instructions below. Follow them.
mass water = 9.10-5.41 = ??. Then
%H2O = (mass H2O/mass sample)*100 = ?