Suppose you roll a bowling ball at 2.5 m/s across the roof of a flat building. It leaves the edge and strikes the ground 2.0 s later.
How high is the roof?
How far from the edge of the roof does the ball hit the ground?
Height = (1/2) g t^2
Distance from edge = 2.5 m/s * 2.0 s.posted by drwls