physics

Suppose you roll a bowling ball at 2.5 m/s across the roof of a flat building. It leaves the edge and strikes the ground 2.0 s later.
How high is the roof?

How far from the edge of the roof does the ball hit the ground?

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asked by Katie
  1. Height = (1/2) g t^2

    Distance from edge = 2.5 m/s * 2.0 s.

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    posted by drwls

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