How much heat is gained (in Joules) by the water where a chemical reaction takes place in 100 mL aqueous solution and has a temperature increase of 14 C?

q=mass water x specific heat water x delta T.

Oh, you're asking about heat? Well, let me tell you, heat is a lot like a bad pun - it can really make you sweat! Now, to answer your question, we can use the formula Q = mcΔT, where Q is the heat gained, m is the mass of the water, c is the specific heat capacity, and ΔT is the change in temperature.

Assuming the density of water is approximately 1 g/mL, we can say that the mass of the water is 100 grams. The specific heat capacity of water is around 4.18 J/g·°C. So now we can plug those numbers in:

Q = (100 g)(4.18 J/g·°C)(14 °C)

Calculating that, we get:

Q ≈ 5872 J

So, the water gains approximately 5872 Joules of heat. Now that's hot stuff!

To calculate the heat gained by the water, you can use the formula:

Q = m * c * ΔT

where:
Q = heat gained (in Joules)
m = mass of water (in grams)
c = specific heat capacity of water (4.184 J/g°C)
ΔT = temperature change (in °C)

First, you need to convert the volume of the solution (100 mL) to mass. The density of water is approximately 1 g/mL, so the mass of the solution is 100 g.

Next, substitute the values into the formula:

Q = 100 g * 4.184 J/g°C * 14°C

Q = 58,576 J

Therefore, the water gains 58,576 Joules of heat.

To calculate the heat gained by the water during a chemical reaction, we can use the formula:

Q = m * C * ΔT

Where:
Q is the heat gained or lost (in joules),
m is the mass of the water (in grams),
C is the specific heat capacity of water (4.18 J/g°C), and
ΔT is the change in temperature (in °C).

First, we need to convert the volume of the water (100 mL) into grams. To do this, we can use the density of water, which is approximately 1 g/mL. Therefore, the mass of water is:

m = Volume * Density
m = 100 mL * 1 g/mL
m = 100 g

Next, we can substitute the values into the formula:

Q = 100 g * 4.18 J/g°C * 14°C

Calculating the equation:

Q = 100 g * 4.18 J/g°C * 14°C
Q = 5868 J

Therefore, the heat gained by the water during the reaction is 5868 Joules.