find dy/ds

y = s*square root of(1-s^2) + cos inverse(s)

Just give me some hints and I will do it. Thanks.


You have
y = s*square root of(1-s^2) + cos inverse(s)
which I would write as
y = s*sqrt(1-s2) + cos-1(s)
and you want dy/ds
For the first term use the product rule. You should know how to differentiate the square root by now if you're doing a problem like this.
For the second term, cos-1(u)
d/du cos-1(u) = -1/sqrt(1-u2)
Can you take it from here?

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