Ni+4CO=NI(CO)4

this reaction separates nickel from other solid impurities.Starting with 86.4g NI,calculte the pressure of NI(CO)4 in a container of volume

To Drbobb222, after using the formular u gave. PV=nRT moles for NI(CO)4 is 171 and the volume is 4, multiply that rite? Then multiply it to 86.4/6.o22E23 rite?

Where did the 0.022E23 come from?

How many moles Ni did you find in the 86.4 g Ni?
How many moles Ni(CO)4 does this produce?
Then PV = nRT.
You don't list a T in the problem. Is that room temperature or what?
P = nRT/V and I obtained something like 1.5 or so mols Ni(CO)4.

To calculate the pressure of NI(CO)4 in a container of volume, you can use the Ideal Gas Law equation: PV = nRT.

1. First, determine the number of moles of NI(CO)4. Given that the reaction starts with 86.4 g of NI, you need to convert the grams of NI to moles. The molar mass of NI is 58.6934 g/mol. So, divide the mass of NI by its molar mass to get the number of moles:

Moles of NI = 86.4 g / 58.6934 g/mol

2. Since Ni+4CO = NI(CO)4, and there is a 1:1 stoichiometric ratio between Ni and NI(CO)4, the number of moles of NI(CO)4 is the same as the number of moles of Ni.

Moles of NI(CO)4 = 86.4 g / 58.6934 g/mol

3. Next, you need to calculate the actual number of moles of NI(CO)4. To do this, you can multiply the number of moles of Ni by the coefficient in front of NI(CO)4 in the balanced equation (which is 1):

Actual moles of NI(CO)4 = Moles of NI

4. Now, you can calculate the pressure of NI(CO)4 in the container. For this, you need to know the temperature and the volume of the container. You mentioned that the volume is given, so use that value.

P × V = n × R × T

where:
P = pressure (what we are trying to find)
V = volume (given)
n = actual moles of NI(CO)4 (calculated in step 3)
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)

Plug in the known values and solve for P:

P × V = (Actual moles of NI(CO)4) × R × T

P = (Actual moles of NI(CO)4) × R × T / V

Remember to convert the temperature from Celsius to Kelvin by adding 273.15 to the temperature value.

Now, substitute the values and calculate the pressure.