An athlete whirls in a 7.10-kg hammer tied to the end of a 1.2 m chain in a horizontal circle, as shown in the figure below. The hammer makes one revolution in 1.0 s.

(a) What is the centripetal acceleration of the hammer?

(b) What is the tension in the chain?

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a. 51.2 m/s^2

b. 358.4 N

a 600 kg hammer of pile driver is lifted 2 meters above a piling head. what is the change in potential energy if the hammer is released, what will its speed at the instant it strikes the piling?

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To find the centripetal acceleration of the hammer, we can use the formula:

Centripetal acceleration (a) = (v^2) / r

where v is the linear velocity of the hammer and r is the radius of the circular path.

(a) The hammer makes one revolution in 1.0 s, so we can find the linear velocity using the formula:

Linear velocity (v) = (2πr) / T

where T is the time period for one revolution. In this case, T = 1.0 s.

Given that the radius of the circular path is 1.2 m, we can substitute the values into the equation to find the linear velocity:

v = (2π * 1.2) / 1.0

Now that we know the linear velocity, we can calculate the centripetal acceleration:

a = (v^2) / r

Substituting the value of v and r into the equation, we get the answer for part (a).

(b) To find the tension in the chain, we can use the formula:

Tension (T) = m * a

where m is the mass of the hammer and a is the centripetal acceleration calculated in part (a).

Given that the mass of the hammer is 7.10 kg, we can substitute the values into the equation to find the tension in the chain.