# Physics

A small steel ball bearing with a mass of 24 g is on a short compressed spring. When aimed vertically and suddenly released, the spring sends the bearing to a height of 1.23 m. Calculate the horizontal distance the ball will travel if the same spring is aimed 27° from the horizontal.

For this problem, does the mass need to be considered? Or do I just ignore the mass and solve for the velocities?

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1. Yes, the mass has to be considered. The spring is operating against gravitational forces in the vertical.

energy in spring= massball*g*height

because it is short, you can ignore the change in GPE when the spring is compressed.
If that is so, then
1/2mv^2=mgh and you are right, mass divides out.
v initial= sqrt (2gh)
this is the same v initial when launched at any other angle.

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2. Once I then have the initial vel., how can I go about getting the horizintal distance? Don't I need time?

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posted by Lindsay
3. No,

initial vertical velocity= v*sinTheta

That will lead to time in air.

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4. Ahh ok I got it now.

Thanks. :)

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posted by Lindsay

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