Solve the equation:
2^x^2-4x = (1/16)^x-4
2^(x^2 - 4x) = (1 / 16)^(x - 4).
2^(x^2 - 4x) = (1/ 2^4)^(x - 4),
2^(x^2 - 4x) = (2^-4)^(x - 4),
2^(x^2 - 4x) = (2^(-4x + 16),
The bases are equal(2),thefore the
exponents are equal:
x^2 - 4x = -4x + 16,
x^2 - 4x + 4x = 16,
x^2 = 16,
x = +- 4.
Solution set: x = 4, and x = - 4.