Given the following reaction:

HCl(g) + SrO(s) �¨ SrCl2(s) + H2O
Calculate the mass of HCl in grams that would react with 11.44 kg SrO.

HCl(g) + SrO(s) -> SrCl2(s) + H2O

start with balancing the equation, which will look like this

aHCl(g) + SrO(s) -> cSrCl2(s) + dH2O

This will give you the number of moles of HCl (a) that react with one mole of SrO

calculate the number of moles of SrO in 11.44 kg from

11440/(molar mass of SrO)

the equation will then tell you how many moles of HCl that react with one mole of SrO (=a).

so number of moles of HCl is

11440x(a)/(molar mass of SrO)

mass of HCl is

11440x(a)x(molar mass of HCl)/(molar mass of SrO)

To calculate the mass of HCl that would react with 11.44 kg of SrO, we need to equate the number of moles of SrO to the number of moles of HCl.

First, we need to convert the given mass of SrO to moles. We can use the molar mass of SrO to do this. The molar mass of SrO is the sum of the atomic masses of Sr and O from the periodic table.

The molar mass of Sr is 87.62 g/mol, and the molar mass of O is 16.00 g/mol. Therefore, the molar mass of SrO is 87.62 g/mol + 16.00 g/mol = 103.62 g/mol.

To convert the mass of SrO to moles, we divide the given mass (11.44 kg) by the molar mass:
11.44 kg * 1000 g/kg = 11,440 g
11,440 g / 103.62 g/mol ≈ 110.37 mol

Now that we know the number of moles of SrO, we can use the balanced equation to determine the mole ratio between SrO and HCl.

According to the balanced equation:
1 mole of SrO reacts with 2 moles of HCl.

Therefore, we multiply the number of moles of SrO by the mole ratio:
110.37 mol SrO * (2 mol HCl / 1 mol SrO) = 220.74 mol HCl

Finally, to convert the number of moles of HCl to grams, we multiply by the molar mass of HCl. The molar mass of HCl is the sum of the atomic masses of H and Cl from the periodic table.

The molar mass of H is 1.01 g/mol, and the molar mass of Cl is 35.45 g/mol. Therefore, the molar mass of HCl is 1.01 g/mol + 35.45 g/mol = 36.46 g/mol.

To calculate the mass of HCl in grams, we multiply the number of moles (220.74 mol) by the molar mass of HCl:
220.74 mol HCl * 36.46 g/mol = 8041.55 g

Therefore, the mass of HCl that would react with 11.44 kg of SrO is approximately 8041.55 grams.