If a precipitation reaction occurs when a solution of one species is added to a solution of the other, enter the formulas and states of all products. Separate by comma. If there is no reaction, enter the formula and state of all ions in solution.
CoCl2(aq) + NaOH(aq) →
To determine the formulas and states of the products in the reaction between CoCl2(aq) and NaOH(aq), we can follow the following steps:
Step 1: Write the balanced molecular equation for the reaction.
CoCl2(aq) + 2NaOH(aq) → Co(OH)2(s) + 2NaCl(aq)
Step 2: Determine the formulas and states of the products.
The product on the left side of the arrow is CoCl2(aq), which is a soluble compound. When mixed with NaOH(aq), a precipitation reaction occurs, resulting in the formation of a precipitate (solid) and a soluble compound.
The product on the right side of the arrow is Co(OH)2(s), which is the precipitate formed in the reaction. It is a solid compound.
The other product is 2NaCl(aq), which is a soluble compound. This compound stays in the solution as individual ions.
Therefore, the formulas and states of all products in the reaction are:
CoCl2(aq), NaOH(aq) → Co(OH)2(s), NaCl(aq)
Note: (aq) represents an aqueous solution, (s) represents a solid precipitate, and no state is indicated for individual ions in a solution.