We consider hemoglobin along a 0.29 m long tube filled with water. The cross-sectional area of the tube is 326 mm2. The diffusion coefficient is 7 x 10^-11 m^2/s A total amount of hemoglobin of 1.22 x 10-12 g is transported in a steady rate along the tube in 24 seconds. What is the difference in the density levels of hemoglobin at the two ends of the tube?

Express the result in the unit [g/cm3] and to three significant figures.

To find the difference in the density levels of hemoglobin at the two ends of the tube, we need to know the rate of transport of hemoglobin and the volume of the tube.

The rate of transport of hemoglobin can be calculated using the given total amount and time:
Rate of transport = Total amount / Time
Rate of transport = (1.22 x 10^-12 g) / (24 s)

To find the volume of the tube, we need to multiply the cross-sectional area by the length:
Volume of the tube = Cross-sectional area x Length
Volume of the tube = (326 mm^2) x (0.29 m)

Now, let's convert the units:
Volume of the tube = (326 mm^2) x (0.29 m)
Volume of the tube = (326 x 10^-6 m^2) x (0.29 m)
Volume of the tube = 0.09454 x 10^-3 m^3

Now, we can calculate the density difference:
Density difference = Rate of transport / Volume of the tube
Density difference = (1.22 x 10^-12 g) / (24 s) / (0.09454 x 10^-3 m^3)

Let's convert the density difference to the desired unit of [g/cm3]:
Density difference = (1.22 x 10^-12 g) / (24 s) / (0.09454 x 10^-3 m^3) x (1 g / 1 x 10^-3 kg) / (1 kg / 1000 g) / (1 m / 100 cm) / (1 cm^3 / 1 mL)
Density difference = (1.22 x 10^-12 g) / (24 s) / (0.09454 x 10^-3 m^3) x (1 g / 1 x 10^-3 kg) / (1 kg / 1000 g) / (1 m / 100 cm) / (1 cm^3 / 1 mL)
Density difference ≈ 545.2 g/cm^3

Therefore, the density difference of hemoglobin at the two ends of the tube is approximately 545.2 g/cm^3.