A uniform magnetic field points North; its magnitude is 1.5 T. A proton with kinetic energy 8.0x10–13 J (5.0 MeV) is moving vertically downward in this field. What is the magnetic force acting on it?
I have no idea where to start with this question, can I just have the formula's I would need to work it out?
Thanks:)
F=qvB(sinθ) but sinθ=1 so we can ignore it.
We have B =1.5T
q=1.6x10^-19
We just need v from our Ke.
Ke=1/2mv^2
v^2=2Ke/m
Punch in 8.0x10^13J and look up the mass of a proton (1.672x10^27) and solve for v, which turns out to be 3.09x10^7.
F=(1.6x10^-19)(3.09x10^7)(1.5)=
7.4x10^-12.
If you do the right hand rule you will find out it points east. (Look up right hand rule if you don't know it).
Well, it seems like you're in a bit of a magnetic pickle, but fear not! I'm here to help you out with some magnetic humor and the formulas you need.
To calculate the magnetic force on a charged particle moving through a magnetic field, you would use the formula:
F = q * v * B * sin(theta),
where F is the magnetic force, q is the charge of the particle, v is its velocity, B is the magnetic field strength, and theta is the angle between the velocity vector and the magnetic field vector.
In this case, we are dealing with a proton, which has a charge of +1.6 × 10^(-19) C. The magnitude of the magnetic field is given as 1.5 T, and the kinetic energy of the proton is 8.0 × 10^(-13) J.
Since the proton is moving vertically downward, we can assume that the angle between its velocity and the magnetic field is 90 degrees, so sin(theta) = 1.
Now all you have to do is substitute the values into the formula, and you'll get the magnetic force acting on the proton.
But hey, here's a bonus for you: Why did the proton bring a compass to the party? Because it wanted to dance with the magnetic fields!
I hope that helps, and remember, funny formulas make physics more attractive!
To calculate the magnetic force acting on the proton, you can use the formula for the magnetic force on a charged particle moving in a magnetic field:
F = q * v * B * sin(θ)
Where:
F is the magnetic force,
q is the charge of the particle (in this case, the charge of a proton, which is +1.6 x 10^-19 C),
v is the velocity of the particle,
B is the magnetic field strength, and
θ is the angle between the velocity vector and the magnetic field vector.
In this case, the proton is moving vertically downward, so the angle between its velocity vector and the magnetic field vector is 90 degrees, giving us sin(θ) = 1.
Using the given values:
q = +1.6 x 10^-19 C
v = velocity of the proton (which we need to determine from the given kinetic energy)
B = 1.5 T
Now, let's calculate the velocity of the proton (v) using the given kinetic energy.
The kinetic energy of a proton is given by:
K.E. = (1/2) * m * v^2
Where:
K.E. is the kinetic energy,
m is the mass of the proton (1.67 x 10^-27 kg),
v is the velocity of the proton.
From the given kinetic energy, we can solve for v:
8.0 x 10^-13 J = (1/2) * (1.67 x 10^-27 kg) * v^2
Solving the equation for v^2:
v^2 = (2 * 8.0 x 10^-13 J) / (1.67 x 10^-27 kg)
v^2 = 9.58 x 10^14 m^2/s^2
Taking the square root of both sides to find v:
v = √(9.58 x 10^14 m^2/s^2)
Now that we have the velocity of the proton (v), we can substitute all the values into the equation for the magnetic force:
F = (1.6 x 10^-19 C) * v * (1.5 T) * sin(90 degrees)
Of course! To calculate the magnetic force acting on a charged particle moving in a magnetic field, you can use the formula for the magnetic force:
F = q * v * B * sin(θ)
Where:
F is the magnetic force acting on the charged particle,
q is the charge of the particle,
v is the velocity of the particle,
B is the magnetic field strength, and
θ is the angle between the velocity vector of the particle and the magnetic field.
In this case, the proton has a charge of q = +1.6 x 10^-19 C (Coulombs), and the magnetic field is given as B = 1.5 T (Tesla), pointing North.
To find the magnetic force, we need to determine the velocity and angle. The velocity of the proton is not directly given, but we can calculate it using its kinetic energy.
The kinetic energy of a moving particle can be calculated using the formula:
KE = (1/2) * m * v^2
Where:
KE is the kinetic energy of the particle,
m is the mass of the particle, and
v is the velocity of the particle.
Given that the proton has a kinetic energy of 8.0 x 10^-13 J (Joules), we need to find the velocity (v). The mass of a proton (m) is approximately 1.67 x 10^-27 kg.
By rearranging the kinetic energy formula, we can solve for v:
v = sqrt((2 * KE) / m)
Once you find the velocity, we can proceed to calculate the angle (θ). In this case, the proton is moving vertically downward. Since the magnetic field is pointing North, the angle between the velocity vector and the magnetic field is 90 degrees.
Plugging in the values of q, v, B, and θ into the magnetic force formula will give you the answer.